The solution set of the inequality 1x-2-1x-2x-2 is - then

The correct options are A α+β+γ+δ=5 D αβγ=0 1 x 2 #10; 1 x 2 x+2 ≤ 0 x( x+2 ) #10; ( x ^ 2 4 ) 2x( x 2 ) #160; x( x 2 # ...

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Sum of Infinite Terms

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Question

The solution set of the inequality $\frac{1}{x - 2} - \frac{1}{x} \leq \frac{2}{x + 2}$ is $(- α, β] \cup (γ, α) \cup [δ, \infty)$ , then

α + β + γ + δ = 5

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α β γ δ = - 4

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β δ = - 2

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α β γ = 0

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