Question

The solution set of the inequation $\frac{2x-1}{3}-\frac{3}{5}x+1<0,xϵW$ is.

• A. Null set
• B. $xϵN$
• C. $xϵR$
• D. $xϵQ$

Answer 1

Answer: (A)

Null set

$\frac{2x-1}{3}-\frac{3}{5}x+1<0$

Multiplying both sides by $15$, we get

$\frac{2x-1}{3}\times 15-\frac{3}{5}x\times 15+1\times 15<0$

$\Rightarrow 5(2x-1)-9x+15<0$

$\Rightarrow 10x-5-9x+15<0$

$10x-9x-5+15<0$

$\Rightarrow x+10<0$

$\Rightarrow x<-10$

Given $x\in W$ (whole number)

Then the solution set of inequation is null set