The solution set of the inequation |x + 1| < 3 is __________.

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Solution

$|x + 1| < 3 i . e . - 3 < x + 1 < 3 i . e . - 3 < x + 1 < 3 By adding - 1, throughout the inequality We get, - 3 - 1 < x + 1 - 1 < 3 - 1 i . e . - 4 < x < 2 i . e . x \in (- 4, 2) ∴ Solution set of |x + 1| < 3 is (- 4, 2)$

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