Question

The solution set of the inequation |x + 2| > 5 is

Answer 1

$$\begin{gathered} \mathrm{for}\left|x+2\right|>5 \\ \mathrm{We}\mathrm{get}, \\ x+2>5\mathrm{or}x+2<-5 \\ \mathrm{i}.\mathrm{e}.x>3(\mathrm{By}\mathrm{adding}-2\mathrm{to}\mathrm{both}\mathrm{sides}\mathrm{of}x+2>5) \\ \mathrm{and}x<-7(\mathrm{By}\mathrm{adding}-2\mathrm{to}\mathrm{both}\mathrm{sides}\mathrm{of}x+2<-5) \\ \mathrm{Hence},\mathrm{solution}\mathrm{set}\mathrm{of}\left|x+2\right|>5\mathrm{is} \\ (-\infty ,-7)\cup (3,\infty ) \end{gathered}$$