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Method of Intervals

The solution ...

Question

The solution set of $x^{2} + 1 < 10$ is

[- 3, 3]

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(- 3, 3)

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R

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ϕ (empty set)

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Solution

The correct option is B $(- 3, 3)$
$x^{2} + 1 < 10 \Rightarrow x^{2} - 9 < 0 \Rightarrow (x + 3) (x - 3) < 0$

$∴ x \in (- 3, 3)$

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