The solution set of $x^{2} < 3 x + 10$ is given by the inequality

x < 5

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x > - 2

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- 2 < x < 5

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-2

\leq

\leq

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x > 5

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Solution

The correct option is B $- 2 < x < 5$
Given, $x^{2} < 3 x + 10$
We get $x^{2} - 3 x - 10 < 0$ $\Rightarrow x^{2} - 5 x + 2 x - 10 < 0$
We get $(x - 5) (x + 2) < 0$
Therefore, we get $- 2 < x < 5$

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