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Method of Intervals

The solution ...

Question

The solution set of $x^{3} - 10 x^{2} + 21 x > 0$ is

A

(0, 3)

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B

(0, \infty)

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C

(3, 7)

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D

(0, 3) \cup (7, \infty)

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Solution

The correct option is D $(0, 3) \cup (7, \infty)$
$x^{3} - 10 x^{2} + 21 x > 0 \Rightarrow x (x - 3) (x - 7) > 0$

$∴ x \in (0, 3) \cup (7, \infty)$

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Method of Intervals

Standard XII Mathematics

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