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Method of Intervals

The solution ...

Question

The solution set of $x^{4} - 8 x^{2} - 9 \leq 0$ is

A

(- 3, 3)

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B

(0, 3)

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C

[- 3, 3]

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D

[3, \infty)

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Solution

The correct option is C $[- 3, 3]$
$x^{4} - 8 x^{2} - 9 \leq 0 \Rightarrow (x^{2} + 1) (x^{2} - 9) \leq 0 \Rightarrow (x + 3) (x - 3) \leq 0$

$∴ x \in [- 3, 3]$

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Method of Intervals

Standard XIII Mathematics

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