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Question

The solution set x= (b1c2b2c1)(a1b2a2b1) and y= (c1a2c2a1)(a1b2a2b1) to the pair of linear equations given below can be written as:

a1x + b1y + c1=0 and a2x + b2y + c2=0 .


A

x/b2c2-b1c1 = y/a2c2-a1c1 = 1/b2a2-b1a1

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B

x/b1c2−b2c1 = y/a2c1−a1c2 = 1/b2a1−b1a2

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C

x/b2c1−b1c1 = y/a2c1−a1c1 = 1/b2a1−b1a2

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D

None of these

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Solution

The correct option is B

x/b1c2−b2c1 = y/a2c1−a1c2 = 1/b2a1−b1a2


We have x = b1c2b2c1(a1b2a2b1 and y = c1a2c2a1a1b2a2b1

We can write this as xb1c2b2c1 = ya2c1a1c2 = 1b2a1b1a2

This is the basis for cross multiplication method.


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