The solution the differential equation dydx2-dtdxex-e-x-1-0 is-are

You visited us 3 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

Chain Rule of Differentiation

The solution ...

Question

The solution the differential equation ${(\frac{d y}{d x})}^{2} - \frac{d t}{d x} (e^{x} + e^{- x}) + 1 = 0$ is/are

y + e^{- x} = c

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

y - e^{- x} = c

No worries! We‘ve got your back. Try BYJU‘S free classes today!

y + e^{x} = c

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

y - e^{x} = c

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct options are
A $y + e^{- x} = c$
C $y + e^{x} = c$

Suggest Corrections

Similar questions

The general solution of the differential equation $\frac{d y}{d x} = e^{x + y}$ is
(a) $e^{x} + e^{- y} = C$
(b) $e^{x} + e^{y} = C$
(c) $e^{- x} + e^{y} = C$
(d) $e^{- x} + e^{- y} = C$

Q. The general solution of the differential equation

\frac{d y}{d x} = e^{x + y}

, is
(a) e^x+ e^−y = C
(b) e^x + e^y = C
(c) e⁻^x + e^y = C
(d) e^−x + e^−y = C

Q. The solution of the differential equation

\frac{d y}{d x} + 1 = e^{x + y}

, is
(a) (x + y) e^x^{+ y} = 0
(b) (x + C) e^x^{+ y} = 0
(c) (x − C) e^x^{+ y} = 1
(d) (x − C) e^x^{+ y}+ 1 =0

The general solution of the differential equation $e^{x} d y + (y e^{x} + 2 x) d x = 0$ is

a) $x e^{y} + x^{2} = C$

b) $x e^{y} + y^{2} = C$

c) $y e^{x} + x^{2} = C$

d) $y e^{y} + x^{2} = C$

Q. The general solution of the differential equation

(1 + e^{\frac{x}{y}}) d x + (1 - \frac{x}{y}) e^{\frac{x}{y}} d y = 0

is (

c

is an arbitary constant)

Join BYJU'S Learning Program

The solution the differential equation (dydx)2−dtdx(ex+e−x)+1=0 is/are

The correct options are A y+e−x=c C y+ex=c

The solution the differential equation ${(\frac{d y}{d x})}^{2} - \frac{d t}{d x} (e^{x} + e^{- x}) + 1 = 0$ is/are

The correct options are
A $y + e^{- x} = c$
C $y + e^{x} = c$