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Question

The solutions of the equation 4cos2x+6sin2x=5 are


A

x = nπ ± π / 4, nϵZ

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B

x = nπ ± π /3, nϵZ

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C

x = nπ ± π /2, nϵZ

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D

x = nπ ± 2π /3, nϵZ

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Solution

The correct option is A

x = nπ ± π / 4, nϵZ


Given,4cos2x+6sin2x=54(cos2x+sin2x)+2sin2x=52sin2x=54sin2x=12x=nπ±π4, nZ


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