wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The soultion of 3excos2ydx+(1ex)cotydy=0 is

Open in App
Solution

Given,

3excos2ydx+(1ex)cotydy=0

3excos2ydx=(ex1)cotydy

3exex1dx=cotycos2ydy

integrating on both sides, we get,

3exex1dx=cotycos2ydy

3exex1dx=secysinydy

3log(ex1)=log(tany)+c


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
General and Particular Solutions of a DE
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon