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Question

The sound level at a point 5.0 m away from a point source is 40 dB. What will be the level at a point 50 m away from the source ?


Solution

We know that, β=10log10(II0)

(a)βA=10logIAI0βB=10logIBI0

IAI0=10(βA10)

IBI0=10(βB10)

IAIB=r2Br2A=(505)2

βAβB10=2log10

(βAβB10)=20

βAβB=20

βB=4020=20dβ

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