Question

The space between plates of a capacitor is filled up with two dielectrics of $K$ = 3 and $K$ = 6. If the electric field strength between plates of $K$ = 3 and in $K$ = 6 are $E_{1}and{E}_2$ respectively, then the value $\frac{E_1}{E_2}$ is

• A. $\frac{1}{2}$
• B. $2$
• C. $1$
• D. $4$

Answer 1

The correct option is C $1$

The electric field strength in a capacitor is directly proportional to the voltage applied and inversely proportional to the distance between the plates,
$\Rightarrow E=\frac{V}{d}$
Since capacitor plates are equipotential, hence $V$ is same in both cases and $d$ is also same for both regions.
Therefore $\frac{E_1}{E_2}=1$