Question

The space between the plates of a parallel plate capacitor is compeletely filled with a material of resistivity $2\times {10}^{11}\Omega \text{m}$ and dielectric constant $6$ capacity of the capacitor with the given dielectric medium between the plates is $20\text{nF}$. The leakage current(in $\mu \text{A}$) if a potential difference $2500\text{V}$ is applied across the capacitor is

• A. 4.7
• B. 4.70

Answer 1

Answer: (A), (B)

leakage current
$I=\frac{V}{R}=\frac{VA}{\rho L}=\frac{V}{\rho }\frac{C}{K{\epsilon }_0}$$(\because C=\frac{{\epsilon }_{0}KA}{L})$



$I=\frac{2500\times 20\times {10}^{-9}}{2\times {10}^{11}\times 6\times 8.85\times {10}^{-12}}$

$I=4.7\times {10}^{-6}\text{A}$

$I=4.7\mu \text{A}$