The space mean speed (kmph) & density (vehicles/km) of a traffic stream are linearly related. The free flow speed and Jam density are 120 kmph and 150 vehicles/km respectively. The traffic flow (in vehicles/hr upto one decimal place) corresponding to 60 kmph is _________

4500

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Solution

The correct option is A 4500
$V_{f} = 120 k m p h$
$k_{j} = 150 v e h / k m$
Flow , q = kv
We know, $V = V_{f} - \frac{V_{f}}{K_{j}} K$
$60 = 120 - \frac{120}{150} k$
$\Rightarrow k = 75 v e h / k m$
$∴ q = k v = 75 \times 60 = 4500 v e h / h r$

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The space mean speed (kmph) & density (vehicles/km) of a traffic stream are linearly related. The free flow speed and Jam density are 120 kmph and 150 vehicles/km respectively. The traffic flow (in vehicles/hr upto one decimal place) corresponding to 60 kmph is _________ 4500

The correct option is A 4500Vf=120 kmph kj=150 veh/km Flow , q = kv We know, V=Vf−VfKjK 60=120−120150k ⇒k=75 veh/km ∴q=kv=75×60=4500 veh/hr

The space mean speed (kmph) & density (vehicles/km) of a traffic stream are linearly related. The free flow speed and Jam density are 120 kmph and 150 vehicles/km respectively. The traffic flow (in vehicles/hr upto one decimal place) corresponding to 60 kmph is _________

4500

The correct option is A 4500
$V_{f} = 120 k m p h$
$k_{j} = 150 v e h / k m$
Flow , q = kv
We know, $V = V_{f} - \frac{V_{f}}{K_{j}} K$
$60 = 120 - \frac{120}{150} k$
$\Rightarrow k = 75 v e h / k m$
$∴ q = k v = 75 \times 60 = 4500 v e h / h r$