The correct option is D [Ni(Cl)4]2−
For the coordination number 4, strong field ligands give square planar complexes. CN− is a strong field ligand, so [Ni(CN)4]2− has a square planner geometry.
As we move from the first to the second transition series, the crystal field splitting energy increases. Hence, the second transition series form square planar complexes. So, [PdCl4]2− and [Pd(CN)4]2− have square planar geometry.
Hence (d) is the correct answer.