Question

The species having tetrahedral shape is :

• A. $[PdC{l}_4{]}^{2-}$
• B. $\left[Ni\right(CN{)}_4{]}^{2-}$
• C. $\left[Pt\right(CN{)}_4{]}^{2-}$
• D. $[NiC{l}_4{]}^{2-}$

Answer 1

Answer: (D)

$[NiC{l}_4{]}^{2-}$

$[NiC{l}_4{]}^{2-}$ have tetrahedral shape while $\left[Ni\right(CN{)}_4{]}^{2-}$ have square planner structure.

The magnetic moment of $[NiC{l}_4{]}^{2-}$ reveals that the species is paramagnetic having two unpaired electrons i.e., $N{i}^{2+}$ is $3d^8$. The four electron pairs by $C{l}^{-}$ ligand leads to $s{p}^3$ - hybridization in $N{i}^{2+}$ and do not disturb $N{i}^{2+}$ configuration to give tetrahedral geometry.