The species in which the central atom uses $s p^{2}$ -hybrid orbitals in its bonding is :

P H_{3}

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N H_{3}

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C H_{3}^{+}

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S b H_{3}

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Solution

The correct option is C $C H_{3}^{+}$
In $C H_{3}^{+}$ the carbon atom is $s p^{2}$ as it contains three bond pairs and zero lone pairs of electrons.
In ammonia $(N H_{3})$ , $N$ atom is $s p^{3}$ (3 bond pairs and 1 lone pair) hybridized whereas in others, pure p orbitals are used.

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Similar questions

S P^{2}

s p^{2}

1. S b H_{3} > N H_{3} > A s H_{3} > P H_{3}

2. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

3. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

4. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

1. S b H_{3} > N H_{3} > A s H_{3} > P H_{3}

2. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

3. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

4. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

N H_{3}, P H_{3}, A s H_{3}, S b H_{3}

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