The species that does not contains peroxide linkage is:

N a_{2} O_{2}

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H_{2} O_{2}

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B a O_{2}

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P b O_{2}

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Solution

The correct option is D $P b O_{2}$
In $P b O_{2},$ $P b$ can accomodat $+ 4$ oxidation state.
But all other elements $N a, H and B a$ can not form $+ 4$ oxidation state and have peroxide linkage.

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The species that does not contain peroxide ions is:

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