The species that undergoes disproportiation in alkaline medium is :

{C l}_{2}

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C l O_{4}

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N O_{2}

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M n O_{4}^{2}

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Solution

The correct option is B ${C l}_{2}$
$C l_{2} + 6 H_{2} O \to 2 C l O_{3}^{-} + 12 H^{(+)} + 10 e^{-}$
$C l_{2} + 2 e^{-} \to 2 C l^{-}$
$∴ C l_{2}$ undergoes dispropornation in alkaline medium

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The charge required for the oxidation of one mole $M n_{3} O_{4}$ into $M n O {_{4}}^{2 -}$ in presence of alkaline medium is :

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