The species which are isoelectronic with CO is:

C l^{-}

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O H^{-}

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C H_{3}^{+}

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N_{2}

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Solution

The correct option is D $N_{2}$
The molecules contain same number of electrons is known as isoelectronic and having the same electronic configuration

Given $C O$ molecule having 14 electrons ( 6+8=14 )
$N_{2}$ have also 14 electrons

$C l^{-} \to 18$
$O H^{-} \to 10$
$C H_{3}^{+} \to$ 8

So, the correct answer is $N_{2}$

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S^{2 -}, N a^{+}, C a^{2 +}, C l^{-}

C l^{-} a n d C a^{2 +}

\begin{matrix} C l^{-}, A r, K^{+}, O^{2 -}, M g^{2 +}, F^{-} \end{matrix}

C a^{2 +}

Statement - I: $C l^{-} a n d C a^{2 +}$ are isoelectronic species.
Statement - II: Isoelectronic species should have same charges.

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