The species with a radius less than of Ne is

a)Mg2+

b)F-

c)O2-

d)K+

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Solution

Since all the above species have same no of electrons so the given elements are isoelectronic.

The ionic radii of isoelctronic species will increase with decresing magnitude of nuclear charge.

02-<F-<Ne<k+<mg2+

so ions of oxygen and flurine will have less ionic radii than Ne

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