Question

The species with spin only magnetic moment of $\sqrt{24}$ BM is :

• A. $\left[Co{F}_3\right(H_{2}O{)}_3]$
• B. $[CoC{l}_4{]}^{2-}$
• C. $[NiC{l}_4{]}^{2-}$
• D. $\left[Ni\right(H_{2}O{)}_6{]}^{2+}$

Answer 1

The correct option is A $\left[Co{F}_3\right(H_{2}O{)}_3]$

The spin only magnetic moment is given by the formula ${\mu }_{eff}=\sqrt{n(n+2)}B.M.$

The species with spin only magnetic moment of $\sqrt{24}$ BM contains 4 unpaired electrons.

$\left[Co{F}_3\right(H_{2}O{)}_3]$ undergoes $s{p}^3{d}^2$ hybridization to form outer orbital complex with 4 unpaired electrons.

$[CoC{l}_4{]}^{2-}$ undergoes $s{p}^3$ hybridization and contains 3 unpaired electrons.

$[NiC{l}_4{]}^{2-}$ undergoes $s{p}^3$ hybridization and contains 2 unpaired electrons.

$\left[Ni\right(H_{2}O{)}_6{]}^{2+}$ undergoes $s{p}^3{d}^2$ hybridization and contains 2 unpaired electrons.

Hence the correct option is A.