Question

The specific activity of $Cobalt-57$, whose half life is $270$ days, will be

• A. $8478$ $Curie/gm$
• B. $847.8$ $Curie/gm$
• C. $84.78$ $Curie/gm$
• D. $1$ $Curie/gm$

Answer 1

Answer: (A)

$8478$ $Curie/gm$

$a=\frac{4.17\times {10}^{23}}{T_{1/2}M}$

$T_{1/2}=270\times 24\times 3600s$

$a=8478Curie/gm$