Question

The specific conductance at 298 K of AgCl solution In water was determined to be 1.826 x 10${}^{-6}$ ohm${}^{-1}$ cm${}^{-1}$. The ionic conductances Ag${}^{+}$ and $C{l}^{-}$ are 61.92 and 76.34 respectively. What is the solubility of AgCl in water?

• A. 2.1 x 10${}^{-4}$ gL${}^{-1}$
• B. 1.32 x 10${}^{-5}$ gL${}^{-1}$
• C. 1.9 x 10${}^{-3}$ gL${}^{-1}$
• D. 2.1 x 10${}^{-6}$ gL${}^{-1}$

Answer 1

The correct option is B 1.32 x 10${}^{-5}$ gL${}^{-1}$

Speerfre conduetimce $k=1.826\times {10}^{-6}oh{m}^{-1}c{m}^{-1}$

ionic conducpance $AAg+{\stackrel{o}{\lambda }}_{A{g}^{+}}=61.92oh{m}^{-1}c{m}^{2}mo{l}^{-1}$

${\stackrel{o}{\lambda }}_{C{l}^{-}}=76.34oh{m}^{-1}c{m}^{2}mo{l}^{-1}$

${\stackrel{o}{A}}_m\left(Ag4\right)={\stackrel{o}{\lambda }}_{A{g}^{+}}+{\stackrel{o}{\lambda }}_{C{l}^{-}}$

$\stackrel{o}{A}=61.92+76.34=138.26oh{m}^{-1}c{m}^{2}mo{l}^{-1}$

$\stackrel{o}{A}=\frac{K}{C}$

$C=\frac{K}{C}=\frac{1.826\times {10}^{-6}\times 1000}{138.26}$

$=1.32\times {10}^{-5}mol{L}^{-1}$