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Question

The specific conductance of 0.01 M solution of acetic acid was found to be 0.0163 S m1 at 25°C. Calculate the degree of dissociation of the acid. Molar conductance of acetic acid at infinite dilution is 390.7×104 S m2 mol1 at 25°C.

A
0.0632
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B
0.0472
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C
0.0823
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D
0.0984
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Solution

The correct option is B 0.0472
Given,
κ=0.0163 S m1; c=0.01 mol dm3=10 mol m3

Λm=κc=0.0163 S m110 mol m3=16.3×104 S m2 mol1

Λm=390.7×104 S m2 mol1 (given)

α=ΛmΛm=16.3×104S m2 mol1390.7×104S m2 mol1=0.0472

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