Question

The specific conductance of a $0.01M$ solution of $KCl$ is $0.0014oh{m}^{-1}c{m}^{-1}$ at ${25}^{\circ }C$. Its equivalent conductance is____________.

• A. $14$
• B. $140$
• C. $1.4$
• D. $0.14$

Answer 1

The correct option is B $140$

$\kappa =0.0014S{cm}^{-1}{\Lambda }_{eq}=\frac{1000\times \kappa }{C}C=0.01M{\Lambda }_{eq}=\frac{1000\times 0.0014}{0.01}=140$