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Byju's Answer
Standard XII
Chemistry
Conductance and Conductivity
The specific ...
Question
The specific conductance of a saturated solution of AgCl is found to be
1.86
×
10
−
6
o
h
m
−
1
c
m
−
1
and that of water is
6
×
10
−
8
o
h
m
−
1
c
m
−
1
. The solubility of AgCl given that
λ
0
A
g
C
l
=
(
137.2
o
h
m
−
1
c
m
−
1
is
×
10
−
5
M
)
Open in App
Solution
κ
A
g
C
l
=
κ
A
g
C
l
(
s
o
l
u
t
i
o
n
)
−
κ
H
2
O
=
1.86
×
10
−
6
−
6
×
10
−
8
=
1.8
×
10
−
6
o
h
m
−
1
c
m
−
1
λ
0
A
g
C
l
=
k
×
1000
s
s
=
1.31
×
10
−
5
M
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0
Similar questions
Q.
The conductivity of saturated solution of
A
g
C
l
is found to be
1.86
×
10
−
6
o
h
m
−
1
c
m
−
1
and that of water is
6
×
10
−
8
o
h
m
−
1
c
m
−
1
. If
λ
0
A
g
C
l
is 138
o
h
m
−
1
c
m
2
e
q
−
1
the solubility product of
A
g
C
l
is:
Q.
The specific conductance of a saturated solution of
A
g
C
l
at
25
∘
C
is
3.55
×
10
−
6
Ω
−
1
c
m
−
1
and that of water used for preparing the solution is
1.60
×
10
−
6
Ω
−
1
c
m
−
1
. What is the solubility product of AgCl?
(
Λ
∞
(
A
g
C
l
)
=
150.0
Ω
−
1
c
m
2
eqv
−
1
)
Q.
The specific conductance of a saturated solution of
A
g
C
l
at
25
∘
C
is
3.55
×
10
−
6
Ω
−
1
c
m
−
1
and that of water used for preparing the solution is
1.60
×
10
−
6
Ω
−
1
c
m
−
1
. What is the solubility product of AgCl?
(
Λ
∞
(
A
g
C
l
)
=
150.0
Ω
−
1
c
m
2
eqv
−
1
)
Q.
For a saturated solution of AgCl at
25
0
C
,
K
=
3.4
×
10
−
6
o
h
m
−
1
c
m
−
1
and that of
H
2
O
(
l
)
used is
2.02
×
10
−
6
o
h
m
−
1
.
λ
0
m
for AgCl is 138
o
h
m
−
1
c
m
2
m
o
l
−
1
.
The solubility of
A
g
C
l
in moles per liter is a
×
10
−
5
. Find a.
Q.
The specific conductance of
A
g
C
l
at 298 K is
2.326
×
10
−
6
o
h
m
−
1
c
m
−
1
.
The ionic conductivities of
A
g
+
and
C
l
−
ions are
71.92
and
86.34
o
h
m
−
1
c
m
2
m
o
l
−
1
respectively. What is the solubility of
A
g
C
l
in water? (Molarmass of
A
g
C
l
is
143.5
g
m
o
l
−
1
)
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