Question

The specific conductance of a saturated solution of AgCl is found to be $1.86\times {10}^{-6}oh{m}^{-1}c{m}^{-1}$ and that of water is $6\times {10}^{-8}oh{m}^{-1}c{m}^{-1}$. The solubility of AgCl given that${\lambda }_A^{0}gCl=(137.2oh{m}^{-1}c{m}^{-1}$ is $\times {10}^{-5}M$)

Answer 1

${\kappa }_{AgCl}={\kappa }_{AgCl}\left(solution\right)-{\kappa }_{H_{2}O}$
$=1.86\times {10}^{-6}-6\times {10}^{-8}=1.8\times {10}^{-6}oh{m}^{-1}c{m}^{-1}$
${\lambda }_{AgCl=\frac{k\times 1000}{s}}^0$
$s=1.31\times {10}^{-5}M$