Question

The specific conductance of saturated solution of $AgCl$ is found to be $1.86\times {10}^{-6}oh{m}^{-1}c{m}^{-1}$ and that of water is $6\times {10}^{-8}oh{m}^{-1}c{m}^{-1}$. The solubility of $AgCl$ is ________ .
Given, ${\wedge }_{AgCl}^{\circ }=137.2oh{m}^{-1}c{m}^{2}e{q}^{-1}$.

• A. $1.7\times {10}^{-3}M$
• B. $1.3\times {10}^{-5}M$
• C. $1.3\times {10}^{-4}M$
• D. $1.3\times {10}^{-6}M$

Answer 1

Answer: (B)

$1.3\times {10}^{-5}M$

$K_{AgCl}=K_{AgCl\left(Solution\right)}-K_{H_{2}O}$
$=1.86\times {10}^{-6}-6\times {10}^{-8}=1.8\times {10}^{-6}oh{m}^{-1}c{m}^{-1}$
${\wedge }_{AgCl}^{\circ }=K\times \frac{1000}{S}$
$\therefore S=\frac{k\times 1000}{{\wedge }_{AgCl}^{\circ }}=\frac{1.8\times {10}^{-6}\times 1000}{137.2}=1.31\times {10}^{-5}M$.