Question

The specific conductance of saturated solution of AgCl is found to be $1.86\times {10}^{-6}oh{m}^{-1}c{m}^{-1}$ and that of water is $6\times {10}^{-8}oh{m}^{-1}c{m}^{-1}$. The solubility of AgCl given that ${\wedge }_{AgCl}^{\circ }$ = $137.2oh{m}^{-1}c{m}^{2}e{q}^{-1}$ is

• A.
• B.
• C.
• D.

Answer 1

The correct option is B

$K_{AgCl}=K_{AgClsolution}-K_{H_{2}O}$

$=1.86\times {10}^{-6}-6\times {10}^{-8}=1.8\times {10}^{-6}oh{m}^{-1}c{m}^{-1}$

${\wedge }_{AgCl}^{\circ }=\frac{k\times 1000}{s}$

$s=\frac{k\times 1000}{{\wedge }_{AgCl}^{\circ }}=\frac{1.86\times {10}^{-6}\times 1000}{137.2}=1.31\times {10}^{-5}M$