The specific conductance of saturated solution of CaF2 is 3-86 -10 - 5 mho cm - 1 and that water used for solution is 0-15 -10 - 5- The specific conductance of CaF2 alone is-

The correct option is B 3.71 ×10^ 5 Given, #160; #160; #160; #160; K_solution = 3.86 ×10^ 5 mho cm^ 1 #160; #160; #160; # ...

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Byju's Answer

Standard XII

Chemistry

Conductance of Electrolytic Solution

The specific ...

Question

The specific conductance of saturated solution of $Ca F_{2}$ is $3.86 \times 10^{- 5} mho c m^{- 1}$ and that water used for solution is $0.15 \times 10^{- 5}$ . The specific conductance of $Ca F_{2}$ alone is:

3.71 \times 10^{- 5}

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4.01 \times 10^{- 5}

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3.7 \times 10^{- 4}

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3.86 \times 10^{- 4}

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Solution

The correct option is B $3.71 \times 10^{- 5}$
Given,
$K_{solution} = 3.86 \times 10^{- 5} mho c m^{- 1}$

$K_{water} = 0.15 \times 10^{- 5} mho c m^{- 1}$

Since, $K_{solution} = K_{water} + K_{Ca F_{2}}$

$3.86 \times 10^{- 5} = 0.15 \times 10^{- 5} + K_{Ca F_{2}}$

$K_{Ca F_{2}} = (3.86 \times 10^{- 5}) - (0.15 \times 10^{- 5})$

$K_{Ca F_{2}} = 3.71 \times 10^{- 5} mho c m^{- 1}$

Hence option (A) is correct.

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Similar questions

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The specific conductance of saturated solution of CaF2 is 3.86×10−5mhocm−1 and that water used for solution is 0.15×10−5. The specific conductance of CaF2 alone is:

The correct option is B 3.71×10−5Given, Ksolution=3.86×10−5mhocm−1 Kwater=0.15×10−5mhocm−1Since, Ksolution=Kwater+KCaF2 3.86×10−5=0.15×10−5+KCaF2 KCaF2=(3.86×10−5)−(0.15×10−5) KCaF2=3.71×10−5mhocm−1Hence option (A) is correct.

The specific conductance of saturated solution of $Ca F_{2}$ is $3.86 \times 10^{- 5} mho c m^{- 1}$ and that water used for solution is $0.15 \times 10^{- 5}$ . The specific conductance of $Ca F_{2}$ alone is: