Question

The specific conductivity of $0.1NKCl$ solution is $0.0129oh{m}^{-1}c{m}^{-1}$. The resistance of the solution in the cell is $100ohm$.

The cell constant of the cell will be:

• A. $1.10$
• B. $1.29$
• C. $0.56$
• D. $2.80$

Answer 1

The correct option is B $1.29$

Specific conductivity $\left(K\right)=\frac{1}{R}\times cellconstant$
Cell constant $=K\times R$
$=0.0129\times 100$

$=1.29$