The specific conductivity of a saturated solution of silver chloride is 2-30- 10-6 mho cm-1 at 25-C- Calculate the solubility of silver chloride at 25-C if -Ag- - 61-9 mho cm2 mol-1 and -Cl- - 76-3 mho cm2 mol-1-

Let the solubility of AgCl be S gram mole per litre Dilution = 1000S ∧_AgCl^∞ = λ_Ag^+ + λ_Cl^ = 61.9 + 76.3 = 138.2 mho cm^2 m ...

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Standard XII

Chemistry

Conductance and Conductivity

The specific ...

Question

The specific conductivity of a saturated solution of silver chloride is $2.30 \times 10^{- 6} m h o c m^{- 1}$ at $25^{\circ} C$ . Calculate the solubility of silver chloride at $25^{\circ} C$ if $λ_{A g^{+}} = 61.9 m h o c m^{2} m o l^{- 1}$ and $λ_{C l^{-}} = 76.3 m h o c m^{2} m o l^{- 1}$ .

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Solution

Let the solubility of $A g C l$ be $S$ gram mole per litre
$D i l u t i o n = \frac{1000}{S}$
$\land_{A g C l}^{\infty} = λ_{A g^{+}} + λ_{C l^{-}}$
$= 61.9 + 76.3$
$= 138.2 m h o c m^{2} m o l^{- 1}$
$S p . c o n d u c t i v i t y \times D i l u t i o n = \land_{A g C l}^{\infty} = 138.2$
$2.30 \times 10^{- 6} \times \frac{1000}{S} = 138.2$
$S = \frac{2.30 \times 10^{- 3}}{138.2} = 1.66 \times 10^{- 4} m o l$ per litre
$= 1.66 \times 10^{- 5} \times 143.5 g L^{- 1} = 2.382 \times 10 -^{- 3} g L^{- 1}$ .

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Similar questions

Q. The specific conductance of a saturated solution of silver chloride at

25^{o} C

after subtracting the specific conductance of water is

2.28 \times 10^{- 4} S m^{- 1}

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$Λ_{m}^{0} (A g C l) = 138.3 \times 10^{- 4} S m^{2} m o l^{- 1}$
$M (A g C l) = 143.5 g m o l^{- 1}$

Q. The specific conductivity of a saturated solution of

A g C l

3.40 \times 10^{- 6} {ohm}^{- 1} {cm}^{- 1}

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. If

λ_{A g +} = 62.3 {ohm}^{- 1} {cm}^{2} {mol}^{- 1}

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λ_{C l^{-}} = 67.7 {ohm}^{- 1} {cm}^{2} {mol}^{- 1}

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[1 mark]

Q. The specific conductance of a saturated solution of AgCl at

25^{\circ} C

after substracting the specific conductance of water is

2.28 \times 10^{- 6} m h o c m^{- 1}

. The solubility product of AgCl at

25^{\circ} C

is (

λ_{A g C l}^{\infty} = 138.3 m h o c m^{2}

)

The specific conductance of a saturated solution of silver chloride is $K Ω^{- 1} c m^{- 1}$ . The limiting ionic conductances of $A g$ $^{+}$ and $C l$ $^{-}$ ions are $x$ and $y$ , respectively. The solubility of silver chloride in g litre $^{- 1}$ is :

[Molar mass of $A g C l = 143.5$ ]

Q. The specific conductance of a saturated solution of AgCl in water is

1.826 \times 10^{- 6} Ω^{- 1} c m^{- 1}

25^{\circ} C

calculate its solubility in water at

25^{\circ} C

.
Given that :-

λ^{\circ} (A g^{+}) = 61.92

λ^{\circ} (C l^{-}) = 76.34

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The specific conductivity of a saturated solution of silver chloride is 2.30×10−6mho cm−1 at 25∘C. Calculate the solubility of silver chloride at 25∘C if λAg+=61.9 mho cm2mol−1 and λCl−=76.3 mho cm2mol−1.

Let the solubility of AgCl be S gram mole per litreDilution=1000S∧∞AgCl=λAg++λCl−=61.9+76.3=138.2 mho cm2mol−1Sp.conductivity×Dilution=∧∞AgCl=138.22.30×10−6×1000S=138.2S=2.30×10−3138.2=1.66×10−4mol per litre=1.66×10−5×143.5 gL−1=2.382×10−−3gL−1.

The specific conductivity of a saturated solution of silver chloride is $2.30 \times 10^{- 6} m h o c m^{- 1}$ at $25^{\circ} C$ . Calculate the solubility of silver chloride at $25^{\circ} C$ if $λ_{A g^{+}} = 61.9 m h o c m^{2} m o l^{- 1}$ and $λ_{C l^{-}} = 76.3 m h o c m^{2} m o l^{- 1}$ .