Question

The specific gravity of ice is $0.9$. The area of the smallest slab of ice of height $0.5m$ floating in fresh water that will just support a $100kg$ man is

• A. $1.5m^2$
• B. $2m^2$
• C. $3m^2$
• D. $4m^2$

Answer 1

Answer: (B)

$2m^2$

wt. of man = 1000 N

wt. of ice = $0.9\times area\times 0.5N$

wt. of water = $1\times area\times 0.5N$

So, wt. of water = wt. of ice + wt. of man

area $\times 0.5=area\times 0.9\times 0.5+2000$

1 area = 20000 = ${2m}^2$