Question

The specific heat at constant volume for monoatomic argon is $0.075kcal/kg-K$, whereas its gram molecular specific heat is $C_v=2.98cal/molK$. The mass of the argon atom is (Avogrado's number $=6.02\times {10}^{23}$ molecules/mol)

• A. $6.60\times {10}^{-23}g$
• B. $3.30\times {10}^{-23}g$
• C. $2.20\times {10}^{-23}g$
• D. $13.20\times {10}^{-23}g$

Answer 1

Answer: (A)

$6.60\times {10}^{-23}g$

Mass of one mole of argon atoms=Gram molecular specific heat/Specific Heat

$=\frac{2.98g}{0.075mol}=39.733g/mol$

Thus mass of one atom of argon=$\frac{39.733}{6.02\times {10}^{23}}g$

$=6.60\times {10}^{-23}g$

Hence correct answer is option A.