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Question

The specific heat for substance A is twice the specific heat of substance B. The same mass of each substance is allowed to gain 50 Joules of heat energy. As a result of the heating process:

A
the temperature of A rises twice as much as B
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B
the temperature of A rises four times as much as B
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C
the temperature of B rises twice as much as A
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D
the temperature of B rises four times as much as A
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E
the temperature of both B and A rise the same amount
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Solution

The correct option is C the temperature of B rises twice as much as A
Let specific heat of substance A is 2c and specific heat of substance B is c ,
we have , heat given Q=mcΔt, where Δt denotes change in temperature ,
so , for substance A, Q=m×2cΔtA
or ΔtA=Q/2mc .........eq1
For substance B , Q=mcΔtB
ΔtB=Q/mc ...................eq2
by eq1 and eq2,
2ΔtA=ΔtB

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