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Question

The specific heat of a gas is found to be 0.075 calories at constant volume and its formula wt is 40. The atomicity of the gas would be:

A
one
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B
two
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C
three
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D
four
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Solution

The correct option is B one
Specific heat of gas is defined as the amount of heat required to raise the temperature of 1 g of substance by 1 K.

Given: CV=0.075 cal/g/K. Therefore 0.075 cal is absorbed by 1 g of the gas at constant volume.

Formula wt of gas is 40 g. So total heat absorbed by the gas is:

CV=40×0.075=3 cal/K/mol.

Since , CpCV=R and R=1.987 cal/K/mol

Cp=CV+R=3+1.9875

Calculating Cp/CV=5/3=1.66

Hence the gas is monatomic. Therefore option A is correct.

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