Question

The specific heat of a gas is found to be $0.075$ calories at constant volume and its formula weight is $40$. The atomicity of the gas would be:

• A. one
• B. two
• C. three
• D. four

Answer 1

The correct option is A one

Total Heat$=40\times 0.075=3$cal$=Cv$

$Cp-Cv=R$

$Cp=Cv+R$

$=3+2$

$=5$cal

$\frac{Cp}{Cv}=\frac{5}{3}$

$=$monoatomic.