wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

The specific heat of a liquid is 800 Joules per kilogram degree Celcius.
How much heat is needed to to raise the temperature of 0.50 kg of the liquid 10.0 Celcius?

A
4000 J
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
40 J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
16,000 J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
160 J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
E
16 J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 4000 J
Given : S=800 J/(kg.oC) m=0.5kg ΔT=10.0oC
Heat required to raise the temperature Q=mS(ΔT)=0.50×800×10=4000 J

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Specific Heat Capacity
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon