Question

The specific heat of a metal is 0.16 cal/g approximate atomic weight would be:

• A. $40$
• B. $16$
• C. $32$
• D. $64$

Answer 1

The correct option is A $40$

Solution:- (A) $40$

According to Dulong's Petit law-

Approx. at. wt. $\times$ Specific heat $=6.4$

$\therefore$ Approximate atomic weight of the metal $=\frac{6.4}{0.16}=40g$.

Hence the approximate atomic weight of the metal will be $40g$.