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Question

The specific heat of a metal is 0.16 cal/g approximate atomic weight would be:


A
40
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B
16
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C
32
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D
64
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Solution

The correct option is A $$40$$
Solution:- (A) $$40$$
According to Dulong's Petit law-
Approx. at. wt. $$\times$$ Specific heat $$= 6.4$$
$$\therefore$$ Approximate atomic weight of the metal $$= \cfrac{6.4}{0.16} = 40 \; g$$.
Hence the approximate atomic weight of the metal will be $$40 \; g$$.

Chemistry

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