The correct option is C 40
Cv for a monoatomic gas at constant volume is 3R2≈3 cal−mol−1K−1
Let the atomic weight of the gas be w
∴w grams of the gas requires the 3 cal of heat to raise its temperature by 1K.
∴ 1 gram of gas will require 3w cal of heat to raise its temperature by 1K.
∴ 1 kg of gas will require 3w kcal of heat to raise its temperature by 1K.
In the question, the above quantity is given to be 0.075 kcal kg−1K−1
∴3w=0.075
Solving this, we get w=40