The specific heat of Argon at constant volume is $0.3122 k j / k g K$ . Find the specific heat of Argon at constant pressure if $R$ $=$ 8.314 kJ/Kmole K. (Molecular weight of argon $=$ $39.95$ )

520.3

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530.2

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230.5

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302.5

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Solution

The correct option is A $520.3$
Given,
$C_{v} = 0.3122 k J / k g . K$
$R = 8.314$
$M = 39.95$
$C_{p} = ?$
We know,

$C_{p} - C_{v} = \frac{R}{M}$

$C_{p} - C_{v} = \frac{8.314}{39.95} = 0.2081$

$C_{p} = 0.3122 + 0.2081 = 0.5203$

$C_{p} = 520.3 J / k g . K$

Option $A$ is the correct answer

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Similar questions

0.3122

8.314

0.075 kcal/kg K

R = 2 cal/mol K

C_{v}

0.075 k c a l / k g K

(R = 2 c a l / m o l K)

0.075 k c a l / k g K

C_{v} = 2.98 c a l / m o l K

= 6.02 \times 10^{23} m o l e c u l e s / m o l

0.075 k c a l / k g - K

C_{v} = 2.98 c a l / m o l K

= 6.02 \times 10^{23}

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