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Standard VI

Chemistry

Interconversion of State

The specific ...

Question

The specific heat of the substance in the liquid state in $c a l k g^{- 1} K^{- 1}$ is $7.50 \times 10^{x}$ . Find the value of $x$ .

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Solution

$Q = m s Δ T$
From the curve for the first part when the temp changes from $0^{o} C$ to $80^{o} C$ , amount of heat added is $800 c a l$ .
Substituting $Q = 800$ and $Δ T = 80$
we get $800 = m \times 0.5 \times 80$ as $s = 0.5$ given
$∴ m = 20 g m s$
For the phase BC, $Q = 600$ $Δ T = 40$
$∴ s = \frac{Q}{m \times 40}$

$∴ s = \frac{600}{20 \times 40} = 0.75 c a l / g m K = 750 c a l / k g K$

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The specific heat of the substance in the liquid state incalkg−1K−1 is 7.50×10x. Find the value of x.

Q=msΔTFrom the curve for the first part when the temp changes from 0oC to 80oC, amount of heat added is 800 cal.Substituting Q=800 and ΔT=80we get 800=m×0.5×80 as s=0.5 given∴m=20gmsFor the phase BC, Q=600 ΔT=40∴s=Qm×40∴s=60020×40=0.75cal/gmK=750cal/kgK

The specific heat of the substance in the liquid state in $c a l k g^{- 1} K^{- 1}$ is $7.50 \times 10^{x}$ . Find the value of $x$ .