Question

The specific heat of water is $4.18J^o{C}^{-1}{g}^{-1}$. How much heat is required to change the temperature of 10.0 grams of water from $4^{\circ }C$ to ${14}^{\circ }C$?

• A. $10.0J$
• B. $41.80J$
• C. $4.18J$
• D. $418J$

Answer 1

The correct option is D $418J$

418 J heat is required to change the temperature of 10.0 grams of water from $4^{o}C$ to ${14}^{o}C$.
The heat required to raise temperature is the product of mass, specific heat and temperature change. It is $10.0\times 4.18\times (14-4)=418J$