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Standard X

Physics

Latent Heat

The specific ...

Question

The specific latent heat of fusion of water is:

(a) 80 cal $g^{- 1}$

(b) 2260 J $g^{- 1}$

(c) 80 J $g^{- 1}$

(d) 336 J $k g^{- 1}$

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Solution

(a) 336 J $k g^{- 1}$

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Similar questions

The S.I. unit of specific latent heat is :

(a) cal $g^{- 1}$

(b) cal $g^{- 1} K^{- 1}$

(d) J $k g^{- 1} K^{- 1}$

10 g of ice at 0 $^{\circ} C$ absorbs 5460 J of heat energy to melt and change t water at 50 $^{\circ} C$ . Calculate the specific latent heat of fusion of ice. (Specific heat capacity of water is 4200 J $K g^{- 1} K^{- 1}$ .

Q. Calculate the mass of steam at

100^{\circ} C

needed to just melt 320 g of ice at

- 10^{\circ} C

. The specific heat of ice

= 0.5 c a l g^{- 1}^{\circ} C^{- 1}

, latent heat of vaporization of steam

= 540 c a l g^{- 1},

specific heat of fusion of ice

= 80 c a l g^{- 1}

Q. A thermos-flask of negligible heat capacity contains 100 g of ice. Calculate the amount of water in the flask after condensation.

(Given that: Latent heat of ice

= 336 J g^{- 1}

, latent heat of steam

= 2260 J g^{- 1}

, specific heat capacity of water

= 4.2 J g^{- 1} C^{- 1}

)

Q. The amount of heat required to raise the temperature of

75 g

of ice at

0^{o} C

to water at

10^{o} C

is:

[latent heat of fusion of ice is

80 c a l / g

, specific heat of water is

1 c a l / g^{o} C

]

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Latent Heat

Standard X Physics

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The specific latent heat of fusion of water is: (a) 80 cal g−1 (b) 2260 J g−1 (c) 80 J g−1 (d) 336 J kg−1

(a) 336 J kg−1

The specific latent heat of fusion of water is:

(a) 80 cal $g^{- 1}$

(b) 2260 J $g^{- 1}$

(c) 80 J $g^{- 1}$

(d) 336 J $k g^{- 1}$

(a) 336 J $k g^{- 1}$