261

You visited us 261 times! Enjoying our articles? Unlock Full Access!

Latent Heat

The specific ...

Question

The specific latent heat of fusion of water is

80 cal g

^{- 1}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2260 J g

^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

80 J g

^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

336 J kg

^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 80 cal g $^{- 1}$
The specific latent heat of fusion of a substance is the amount of heat required to convert unit mass of the solid into the liquid without a change in temperature.
$q = m H_{f}$
$H_{f} = \frac{q}{m}$
here, $H_{f}$ is heat of fusion $= 334 J / g = 80 c a l g^{- 1}$
(1 J/g $=$ 0.238846 cal/g; 1 cal/g $=$ 4.1868 J/g)

Suggest Corrections

Similar questions

The specific latent heat of fusion of water is:

(a) 80 cal $g^{- 1}$

(b) 2260 J $g^{- 1}$

(d) 336 J $k g^{- 1}$

- 10^{\circ} C

100^{\circ} C

c_{i} = 0.5 {cal g}^{- 1}^{\circ} C^{- 1}

c_{w} = 1 {cal g}^{- 1}^{\circ} C^{- 1}

L_{f} = 80 cal/g

L_{v} = 540 cal/g

The S.I. unit of specific latent heat is :

(a) cal $g^{- 1}$

(b) cal $g^{- 1} K^{- 1}$

(d) J $k g^{- 1} K^{- 1}$

5.0 g

20^{o} C

0^{o} C

= 4.2 J g^{- 1} K^{- 1}

= 336 J g^{- 1}

Calculate the amount of heat released when 5.0 g of water at 20 °C is changed into ice at 0 °C.

Specific heat capacity of water = 4.2J g^-1 °C^-1, Specific latent heat of fusion of ice = 336 J g^-1.

Join BYJU'S Learning Program