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First Order Reaction

The specific ...

Question

The specific rate constant of the decomposition of $N_{2} O_{5}$ is $0.008 m i n^{- 1}$ . The volume of $O_{2}$ collected after 20 minute is 16 mL. The volume in ml that would be collected at the end of reaction. $N O_{2}$ formed is dissolved in $C C l_{4}$ is

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Solution

$k = 0.008 / m i n, t = 20 m i n, x = 16 m L$
The unit of the rate constant indicates that it is a first order reaction.
$k = \frac{2.303}{t} l o g \frac{a}{a - x}$
$0.008 = \frac{2.303}{20} l o g \frac{a}{a - 16}$
$l o g \frac{a}{a - 16} = 1.17$
$a = 108.23$
Henc, 108.23 mL would b collectd at the end of reaction.

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