The specific reaction rate constant for a first order reaction is 1×10−2s−1. If the initial concentration is 1M, find the initial rate. What is the reaction rate after two minutes?
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Solution
K=1×10−2s−1
Ao=1M
⇒R=K[Ao]1
⇒R=1×10−2s−1×1M
⇒R=10−2Ms−1⇒ Initial rate
After two minutes,
K=2.303tlogAoA
⇒A=Aoe−kt
⇒A=1e−(10−2×2)
⇒A=0.98M
Thus, Rate= K[A]1
=1×10−2×0.98M
Rate= 9.8×10−3Ms−1⇒ Rate of reaction after two minute